<h2>MIle </h2> <p> Ovo je dobro</p> (a) Tablica <div class="container mt-4"> <table class="table table-bordered text-center"> <tbody> <tr> <td>\( E = mc^2 \) za §§N1§§ </td> <td>\( \int_{a}^{b} x^2 \,dx \)</td> <td rowspan="2"> <svg width="100" height="100" viewBox="0 0 100 100" xmlns="http://www.w3.org/2000/svg"> <circle cx="50" cy="50" r="40" stroke="black" stroke-width="3" fill="red" /> </svg> </td> <td>Običan tekst</td> </tr> <tr> <td>\( a^2 + b^2 = c^2 \)</td> <td>\( \sum_{n=1}^{\infty} \frac{1}{n^2} \)</td> <td rowspan="2"> <svg width="100" height="100" viewBox="0 0 100 100" xmlns="http://www.w3.org/2000/svg"> <rect x="10" y="10" width="80" height="80" stroke="black" stroke-width="3" fill="blue" /> </svg> </td> </tr> <tr> <td colspan="2">\( \lim_{x \to \infty} \frac{1}{x} = 0 \)</td> <td>\( f(x) = \frac{- §§V0(1,50,1)§§}{1 + e^{-x}} \)</td> </tr> </tbody> </table> (b) \( \sqrt[n]{§§V1(1,10,1)§§ } \) §§N2§§ §§N1§§ ```html <div class="container py-4"> <h1 class="mb-4">Kemijski zadaci</h1> <table class="table table-bordered"> <tbody> <tr> <td> <h5>Zadatak 1:</h5> <p> Izračunaj broj molova supstance: <br> Masa = §§V0(50,100,10)§§ g, molarna masa = §§V1(10,20,1)§§ g/mol. <br> Formula: n = masa ÷ molarna masa. </p> </td> <td> <h5>Zadatak 2:</h5> <p> Izračunaj koncentraciju otopine: <br> Broj molova = §§V2(0.5,1,0.1)§§ mol, volumen = §§V3(0.5,2,0.1)§§ L. <br> Formula: C = n ÷ V. </p> </td> </tr> <tr> <td> <h5>Zadatak 3:</h5> <p> Izračunaj postotak čistoće uzorka: <br> Masa čiste tvari = §§V4(20,50,5)§§ g, ukupna masa uzorka = §§V5(100,200,10)§§ g. <br> Formula: Čistoća = (masa čiste tvari ÷ ukupna masa uzorka) × 100. </p> </td> <td> <h5>Zadatak 4:</h5> <p> Izračunaj postotak prinosa proizvoda: <br> Stvarna masa proizvoda = §§V6(30,60,5)§§ g, teoretska masa = §§V7(40,80,5)§§ g. <br> Formula: Prinos = (stvarna masa ÷ teoretska masa) × 100. </p> </td> </tr> <tr> <td colspan="2"> <h5>Zadatak 5:</h5> <p> Izračunaj faktor razrjeđenja otopine: <br> Početna koncentracija = §§V8(0.5,1,0.1)§§ M, konačna koncentracija = §§V9(0.1,0.5,0.05)§§ M. <br> Formula: Faktor razrjeđenja = početna koncentracija ÷ konačna koncentracija. </p> </td> </tr> </tbody> </table> </div> ```