Linearne - 2 nepoznatice vol 1

Sustav linearnih jednadžbi s dvije nepozanice
<h4> Riješi </h4> <p>a) Koliko je ovo \(2x + 3y = §§V1(-10,10,1)§§\) <br> \(5x - y = 2\)</p> <p>b) \(4x - 2y = \frac{1}{2}\) <br> \(3x + 7y = 5 \cdot §§V2(-3,3,1)§§\)</p> <p>c) \(6x + y = 2 \cdot §§V3(1,5,1)§§\) <br> \(2x - 4y = -8\)</p> <p>d) \(§§V4(-5,5,1)§§x + 2y = 3\) <br> \(3x - 5y = 2\)</p> <p>e) \(3x - 4y = 5\) <br> \(2x + y = §§V5(-2,2,1)§§\)</p> <p>f) \(§§V6(1,5,1)§§x + 4y = 10\) <br> \(2x - 3y = 2 \cdot §§V7(-3,3,1)§§\)</p> <p>g) \(§§V8(1,5,1)§§x - 3y = -§§V9(2,8,2)§§\) <br> \(4x + y = 7\)</p> <p>h) \(5x + 2y = 6\) <br> \(3x - y = §§V10(-3,3,1)§§\)</p> <p>i) \(§§V11(1,5,1)§§x + 2y = 3\) <br> \(2x - 5y = 1\)</p> <p>j) \(3x + 4y = 2 \cdot §§V12(-4,4,1)§§\) <br> \(§§V13(-2,2,1)§§x - y = 5\)</p>
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