Mujo

Zbrajanje i oduzimanje do 1000
-<a/b> ili x<sup>2</sup> Ili <div style="white-space: nowrap;"> <div>$$a^3 + b^3 = c^3$$</div> <div>$$ax^2 + bx + c = 0$$</div> </div> Ili <table style="red-space: nowrap;"> <tr> <td>a³ + b³ = c³</td> </tr> <tr> <td>ax² + bx + c = 0</td> </tr> </table> Ili <table> <tr> <td>a³ + b³ = c³</td> </tr> <tr> <td style="border-top: 1px solid black;">&nbsp;</td> </tr> <tr> <td>ax² + bx + c = 0</td> </tr> </table> Uuuu <div style="white-space: nowrap;"> <div>$$\frac{a^3 + b^3}{c^3}$$</div> <div>$$ax^2 + bx + c = 0$$</div> </div> -Rjesava Mujin mali zadatatak iz matematike...znoji se,pati,a Mujo ga posmatra. -"Je li tezak zadatak.?. Procitaj...ja cu ti pomoci." --"Vako babo!..Avdo ima §§V0(18,49,1)§§ jabuka..§§V05(2,4,1)§§ jabuke je poklonio..§§V1(5,11,1)§§ jabuka su mu strule... ...§§V0(1,6,1)§§ jabuke mu je pojeo brat..3 jabuke je sam pojeo... Koliko mu je ostalo?" <Br> Gleda ga Mujo...razmislja,misli...i nakon duzeg vremena rece:"I kazes mali se Avdo zove" <hr class="border-top my-3"> https://www.youtube.com/watch?v=Iuiy9PfywWM /n e^{i \pi} + 1 = 0 <svg width="400" height="400" xmlns="http://www.w3.org/2000/svg"> <!-- X-axis --> <line x1="10" y1="200" x2="390" y2="200" stroke="black" stroke-width="2" /> <!-- Y-axis --> <line x1="200" y1="10" x2="200" y2="390" stroke="black" stroke-width="2" /> <!-- Grid lines --> <g stroke="gray" stroke-dasharray="2 2"> <!-- Vertical grid lines --> <line x1="50" y1="10" x2="50" y2="390" /> <line x1="100" y1="10" x2="100" y2="390" /> <line x1="150" y1="10" x2="150" y2="390" /> <line x1="250" y1="10" x2="250" y2="390" /> <line x1="300" y1="10" x2="300" y2="390" /> <line x1="350" y1="10" x2="350" y2="390" /> <!-- Horizontal grid lines --> <line x1="10" y1="50" x2="390" y2="50" /> <line x1="10" y1="100" x2="390" y2="100" /> <line x1="10" y1="150" x2="390" y2="150" /> <line x1="10" y1="250" x2="390" y2="250" /> <line x1="10" y1="300" x2="390" y2="300" /> <line x1="10" y1="350" x2="390" y2="350" /> </g> </svg> Razumio sam. Evo ispravljenih izraza s uklonjenim \(x\) i dodanim od 5 do 10 varijabli: <p>a) \(§§V1(1,10,1)§§ + __ = 3 - §§V2(2,8,1)§§ + §§V3(1,5,0.5)§§\)</p> <p>b) \(4 - §§V4(1,5,0.5)§§ = 2 + __ - 1\)</p> <p>c) \(§§V5(0,6,1)§§ - __ + 2 = 5 - §§V6(1,7,1)§§\)</p> <p>d) \(§§V7(-4,4,1)§§ + 1 + §§V8(1,5,1)§§ = 2 + §§V9(2,6,1)§§\)</p> <p>e) \(5 + 7 = 3 - 2 + __ - §§V10(0,4,0.5)§§\)</p> <p>f) \(§§V11(2,8,1)§§ - __ + 2 = 4 - 2 - §§V12(1,5,1)§§\)</p> <p>g) \(§§V13(-3,3,0.5)§§ + 4 = 2 - §§V14(1,5,1)§§ + 3\)</p> <p>h) \(4 - 5 = 2 - §§V15(0,6,1)§§\)</p> <p>i) \(§§V16(1,5,1)§§ + 3 = 2 - 3 + __ - §§V17(0,3,0.5)§§\)</p> <p>j) \(§§V18(-2,2,0.5)§§ - 2 = 3 + §§V19(1,5,1)§§\)</p> <H2> 🍏🍐🍊🍋🍑🫐🫐🥯🧈🌭🧇🍞🥐🍫🫘🍫🏐🏸🏓🥅🏌🏽‍♂️🥇🏆🙊🐮🐥🐗🐴🐢🦑🐙🐙 Lion Jabuka </H2>
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