<h4> Popuni prazna mjesta tako da jednakost bude točna.</h4> 🧎🏽 <p>a) §§V0(-5,5,1)§§ + §§V2(5,15,5)§§ = §§V3(-5,5,1)§§ + ___ </p> <p>b) §§V5(2,8,1)§§ - §§V6(3,12,3)§§ = 5 - ___ </p> <p>c) 2 + §§V7(1,5,1)§§ + ___ = 3 + §§V8(1,5,1)§§ </p> <p>d) 8 - §§V9(2,7,1)§§ + ___ = 4 + §§V10(3,8,1)§§ </p> <i> <h6>* c) i d) može biti više od jednog rješenja, tako da je prikazano samo jedna opcija.<h6/></i> <h4> ... malo teže ... </h4> <p>a) §§V18(-3,3,0.5)§§ + __ = 4 - + §§V19(1,5,1)§§ </p> <p>b) 5 - §§V20(2,8,1)§§ = 3 + __ - 2 + 4 </p> <p>c) §§V21(0,10,2)§§ - __ + 3 = 5 - §§V22(1,7,1)§§ </p> <p>d) §§V23(-5,5,1)§§ + 2 + __ = 3 + §§V24(2,10,2)§§ </p> <p>e) 4 + 7 = 2 - 3 + __ - §§V25(0,4,0.5)§§ </p> <p>f) §§V26(1,7,1)§§ - __ + 2 = 5 - 2 - §§V27(1,5,1)§§ </p> <p>g) §§V28(-2,2,0.5)§§ + __ = 2 - __ + §§V29(1,5,1)§§ </p> <p>h) 3 - 5 = 2 - + §§V30(0,6,1)§§ </p> <p>i) §§V31(1,5,1)§§ + 2 = 3 - 2 + __ - §§V32(0,3,0.5)§§ </p> <p>j) §§V33(-4,4,1)§§ - __ = 2 + §§V34(2,6,1)§§ </p> <h4> ... i još ... </h4> <p>a) §§V1(1,10,1)§§ + __ = 3 - + §§V2(2,8,1)§§ </p> <p>b) 4 - §§V3(1,5,0.5)§§ = 2 + __ - 1 </p> <p>c) §§V5(0,6,1)§§ - __ + 2 = 5 - §§V6(1,7,1)§§ </p> <p>d) §§V7(-4,4,1)§§ + 1 + __ = 2 + §§V8(1,5,1)§§ </p> <p>e) 5 + 7 = 3 - 2 + __ - §§V10(0,4,0.5)§§ </p> <p>f) §§V11(2,8,1)§§ - __ + 2 = 4 - 2 - §§V12(1,5,1)§§ </p> <p>g) §§V13(-3,3,0.5)§§ + __ = 2 - §§V14(1,5,1)§§ + 3 </p> <p>h) 4 - 5 = 2 - + §§V15(0,6,1)§§ </p> <p>i) §§V16(1,5,1)§§ + __ = 2 - 3 + 4 - §§V17(0,3,0.5)§§ </p> <p>j) §§V18(-2,2,0.5)§§ - __ = 3 + §§V19(1,5,1)§§ </p>